2500=16s^2+25

Solution for 2500=16s^2+25 equation:

2500=16s^2+25

We move all terms to the left:

2500-(16s^2+25)=0

We get rid of parentheses

-16s^2-25+2500=0

We add all the numbers together, and all the variables

-16s^2+2475=0

a = -16; b = 0; c = +2475;
Δ = b2-4ac
Δ = 02-4·(-16)·2475
Δ = 158400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{158400}=\sqrt{14400*11}=\sqrt{14400}*\sqrt{11}=120\sqrt{11}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120\sqrt{11}}{2*-16}=\frac{0-120\sqrt{11}}{-32}
=-\frac{120\sqrt{11}}{-32}
=-\frac{15\sqrt{11}}{-4}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120\sqrt{11}}{2*-16}=\frac{0+120\sqrt{11}}{-32}
=\frac{120\sqrt{11}}{-32}
=\frac{15\sqrt{11}}{-4}
$